page+376+number+9+(Nick+Moore)

∫ from 2 to 10 of sqrt( x^3 + 1)dx, n=4 using Midpoints f(x) = sqrt( x^3 + 1) dx= (b-a)/n dx = (10-2)/4 dx=2 Midpoint of (2,4), (4,6), (6,8), (8,10)

∫ from 2 to 10 of sqrt( x^3 + 1)dx = 2 ( f(3) + f(5) +f(7) +f(9) )

∫ from 2 to 10 of sqrt( x^3 + 1)dx = 2( sqrt(28) + sqrt(126) + sqrt(344) +sqrt (730)) = 124.1644

I agree!!