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Find if f(x) = 3 for x <3 and f(x) = x for X >3 or x=3 Midpoints at x= 0.5, 1.5, 2.5, 3.5, 4.5 points: (0.5, 3)(1.5, 3)(2.5, 3)(3.5, 3,5)(4.5, 4.5) change x=1 Area= 1(3+3+3+3.5+4.5)= 17

Yes, nicely done. since the definite integral can also be interpreted as the area between the function and the x-axis, could you have just used area formulas from geometry to evaluate this?? Yes, you could also use the area for a rectangle plus the area of a triangle, whose sum would give you the area under the function.