Problem+14



We are only using the right side of the graph because the integral is from 0 to 4. We know that this graph is the same as number 11, except now all the the y values are negative, and our intervals are different.

Therefore, we know the equation of our area is piR^2/4 Our radius is 4

So area is 16pi/4 which is 4pi

But the function lies below the x-axis...what does this mean about the value of the definite integral????????????